Picture this:
You’ve launched your AI solution, and it’s being put to good use.
But suddenly, you’re overwhelmed, manually reviewing every new user query to ensure everything works as intended.
The flood of queries makes it nearly impossible to spot repeats, and it’s eating up your valuable time.
.... What if you could automatically identify new, unique queries without lifting a finger?
After facing this challenge myself, I developed a Python-based system that got rid of a lot of headaches.
- 📚 Automated Similarity Checking: By using cosine similarity (or similar methods), you can automatically compare new user queries against previous ones to identify duplicates or closely related questions.
- 💬 Efficient Query Management: The system flags truly unique queries, allowing you to focus your attention on those.
- 📈 Scalable Solution: As your user base grows, this approach scales effortlessly, handling an increasing number of queries without additional manual effort.
It honestly took me a while to have the structure of the system fully laid out and working, so I can hopefully save you some time with my explanation!
(the loom vid attached showcases the system a bit more in-depth)
But that’s just the tip of the iceberg.
You can take this even further by:
- Automating Response Consistency Checks: Compare new replies to old ones for the same queries to ensure consistent responses.
And integrating additional features to automate your workflows even more.
fyi: there may be better ways to get around solving this issue, this is just the solution I came up with.
By setting up this system, you can:
- Save Time: Drastically reduce the hours spent on manual reviews.
- Increase Efficiency: Quickly identify and address unique issues.
- Scale Effectively: Maintain performance as your user base grows.
If you’re interested in learning more about how to set this up, including detailed steps and code examples, I’ve laid it all out in a recent article.
Ps: if you need help developing solutions, feel free to reach out :) (serious inquiries only please)